Optimal. Leaf size=109 \[ -\frac{b (2 a+b)}{a^2 (a+b)^2 \sqrt{a+b \text{sech}^2(x)}}+\frac{\tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}^2(x)}}{\sqrt{a}}\right )}{a^{5/2}}-\frac{b}{3 a (a+b) \left (a+b \text{sech}^2(x)\right )^{3/2}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}^2(x)}}{\sqrt{a+b}}\right )}{(a+b)^{5/2}} \]
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Rubi [A] time = 0.199893, antiderivative size = 109, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 7, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.467, Rules used = {4139, 446, 85, 152, 156, 63, 208} \[ -\frac{b (2 a+b)}{a^2 (a+b)^2 \sqrt{a+b \text{sech}^2(x)}}+\frac{\tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}^2(x)}}{\sqrt{a}}\right )}{a^{5/2}}-\frac{b}{3 a (a+b) \left (a+b \text{sech}^2(x)\right )^{3/2}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}^2(x)}}{\sqrt{a+b}}\right )}{(a+b)^{5/2}} \]
Antiderivative was successfully verified.
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Rule 4139
Rule 446
Rule 85
Rule 152
Rule 156
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{\coth (x)}{\left (a+b \text{sech}^2(x)\right )^{5/2}} \, dx &=\operatorname{Subst}\left (\int \frac{1}{x \left (-1+x^2\right ) \left (a+b x^2\right )^{5/2}} \, dx,x,\text{sech}(x)\right )\\ &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{1}{(-1+x) x (a+b x)^{5/2}} \, dx,x,\text{sech}^2(x)\right )\\ &=-\frac{b}{3 a (a+b) \left (a+b \text{sech}^2(x)\right )^{3/2}}+\frac{\operatorname{Subst}\left (\int \frac{a+b-b x}{(-1+x) x (a+b x)^{3/2}} \, dx,x,\text{sech}^2(x)\right )}{2 a (a+b)}\\ &=-\frac{b}{3 a (a+b) \left (a+b \text{sech}^2(x)\right )^{3/2}}-\frac{b (2 a+b)}{a^2 (a+b)^2 \sqrt{a+b \text{sech}^2(x)}}-\frac{\operatorname{Subst}\left (\int \frac{-\frac{1}{2} (a+b)^2+\frac{1}{2} b (2 a+b) x}{(-1+x) x \sqrt{a+b x}} \, dx,x,\text{sech}^2(x)\right )}{a^2 (a+b)^2}\\ &=-\frac{b}{3 a (a+b) \left (a+b \text{sech}^2(x)\right )^{3/2}}-\frac{b (2 a+b)}{a^2 (a+b)^2 \sqrt{a+b \text{sech}^2(x)}}-\frac{\operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+b x}} \, dx,x,\text{sech}^2(x)\right )}{2 a^2}+\frac{\operatorname{Subst}\left (\int \frac{1}{(-1+x) \sqrt{a+b x}} \, dx,x,\text{sech}^2(x)\right )}{2 (a+b)^2}\\ &=-\frac{b}{3 a (a+b) \left (a+b \text{sech}^2(x)\right )^{3/2}}-\frac{b (2 a+b)}{a^2 (a+b)^2 \sqrt{a+b \text{sech}^2(x)}}-\frac{\operatorname{Subst}\left (\int \frac{1}{-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b \text{sech}^2(x)}\right )}{a^2 b}+\frac{\operatorname{Subst}\left (\int \frac{1}{-1-\frac{a}{b}+\frac{x^2}{b}} \, dx,x,\sqrt{a+b \text{sech}^2(x)}\right )}{b (a+b)^2}\\ &=\frac{\tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}^2(x)}}{\sqrt{a}}\right )}{a^{5/2}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{a+b \text{sech}^2(x)}}{\sqrt{a+b}}\right )}{(a+b)^{5/2}}-\frac{b}{3 a (a+b) \left (a+b \text{sech}^2(x)\right )^{3/2}}-\frac{b (2 a+b)}{a^2 (a+b)^2 \sqrt{a+b \text{sech}^2(x)}}\\ \end{align*}
Mathematica [B] time = 1.04247, size = 242, normalized size = 2.22 \[ \frac{\text{sech}^5(x) \left (-\frac{2 b \cosh (x) \left (7 a^2+a (7 a+4 b) \cosh (2 x)+16 a b+6 b^2\right ) (a \cosh (2 x)+a+2 b)}{3 a^2 (a+b)^2}-\frac{(a \cosh (2 x)+a+2 b)^{5/2} \left (\sqrt{a} \left (a^2-2 a b-b^2\right ) \tanh ^{-1}\left (\frac{\sqrt{2} \sqrt{a+b} \cosh (x)}{\sqrt{a \cosh (2 x)+a+2 b}}\right )+(a+b)^2 \left (\sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{2 a+2 b} \cosh (x)}{\sqrt{a \cosh (2 x)+a+2 b}}\right )-2 \sqrt{a+b} \log \left (\sqrt{a \cosh (2 x)+a+2 b}+\sqrt{2} \sqrt{a} \cosh (x)\right )\right )\right )}{\sqrt{2} a^{5/2} (a+b)^{5/2}}\right )}{8 \left (a+b \text{sech}^2(x)\right )^{5/2}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.1, size = 0, normalized size = 0. \begin{align*} \int{{\rm coth} \left (x\right ) \left ( a+b \left ({\rm sech} \left (x\right ) \right ) ^{2} \right ) ^{-{\frac{5}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\coth \left (x\right )}{{\left (b \operatorname{sech}\left (x\right )^{2} + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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